Arun
Last Activity: 5 Years ago
w^1 + w^2 + w^3 = 0
w^1 = w^4
w^2 = w^5
1 = w^3 = w^6
Probability that r1 = 1 or 4, r2 = 2 or 5, r3 = 3 or 6
= 2/6 * 2/6 * 2/6
= 1/27
If the values of r1, r2, r3 are reshuffled, then also we will get w^r1 + w^r2 + w^r3 = 0
The values of r1, r2, r3 can be reshuffled in 3! = 6 wats
Therefore, the required probability = 6 * 1/27 = 2/9
Ans: 2/9
